[(x/x+1)+(x/x²-1)]/(x²+x/x²+2x+1)

　　=[x(x-1)/(x²-1)+x/(x²-1)]/[x(x+1)/(x+1)²]

　　=x²/(x²-1)/[x/(x+1)]

　　=x/(x-1)

　　如仍有疑惑,欢迎追问.祝：学习进步!