来自崔亚军的问题
已知函数f(x)=ex-e-x+1(e是自然对数的底数),若f(a)=2,则f(-a)的值为()A.3B.2C.1D.0
已知函数f(x)=ex-e-x+1(e是自然对数的底数),若f(a)=2,则f(-a)的值为()
A.3
B.2
C.1
D.0
1回答
2020-06-20 13:15
已知函数f(x)=ex-e-x+1(e是自然对数的底数),若f(a)=2,则f(-a)的值为()A.3B.2C.1D.0
已知函数f(x)=ex-e-x+1(e是自然对数的底数),若f(a)=2,则f(-a)的值为()
A.3
B.2
C.1
D.0
∵f(x)=ex-e-x+1,
f(a)=2,
∴ea-e-a+1=2,
∴ea-e-a=1,
∴f(-a)=e-a-ea+1=-(ea-e-a)+1=-1+1=0.
故选D.