【分式的计算题,能做几题做几题!1.1/(x^2+3x+2)-查字典问答网
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  【分式的计算题,能做几题做几题!1.1/(x^2+3x+2)+1/(x^2+5x+6)+1/(x^2+4x+3)2.[a/(a-b)-a^2/(a^2-2ab+b^2)]÷[a/(a-b)+a^2/(b^2-a^2)]3.x+2y/(x^2-y^2-z^2-2yz)-x+2y/(y^2+z^2-x^2+2yz)4.b/(a-b+c)+2a+c/(b-a-c)+b-c/(b-a-c))】

  分式的计算题,

  能做几题做几题!

  1.1/(x^2+3x+2)+1/(x^2+5x+6)+1/(x^2+4x+3)

  2.[a/(a-b)-a^2/(a^2-2ab+b^2)]÷[a/(a-b)+a^2/(b^2-a^2)]

  3.x+2y/(x^2-y^2-z^2-2yz)-x+2y/(y^2+z^2-x^2+2yz)

  4.b/(a-b+c)+2a+c/(b-a-c)+b-c/(b-a-c))

1回答
2020-06-20 19:33
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林良超

  1.〔1/(x+1)(x+2)〕+〔1/(x+2)(x+3)〕+〔1/(x+1)(x+3)〕=〔x+3/(x+1)(x+2)(x+3)〕+〔x+1/(x+1)(x+2)(x+3)〕+〔x+2/(x+1)(x+2)(x+3)〕=〔3x+6/(x+1)(x+2)(x+3)〕=3/(x+1)(x+3)2.=[1/(a-b)-a/(a^2-2ab+b^2)]÷[1/(a-b)...

2020-06-20 19:37:10

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