来自蒋良孝的问题
【limx->1x^1/3-1/x$1/4-1,极限x趋向于1,x的三分一次方减去一除以x的四分一次方减去一..求解!谢】
limx->1x^1/3-1/x$1/4-1,极限x趋向于1,x的三分一次方减去一除以x的四分一次方减去一..求解!谢
1回答
2020-06-20 23:43
【limx->1x^1/3-1/x$1/4-1,极限x趋向于1,x的三分一次方减去一除以x的四分一次方减去一..求解!谢】
limx->1x^1/3-1/x$1/4-1,极限x趋向于1,x的三分一次方减去一除以x的四分一次方减去一..求解!谢
x-1=[x^(1/3)-1][x^(2/3)+x^(1/3)+1]x-1=[x^(1/2)+1][x^(1/2)-1]=[x^(1/2)+1][x^(1/4)+1][x^(1/4)-1]原式=lim(x-1)/[x^(2/3)+x^(1/3)+1]×[x^(1/2)+1][x^(1/4)+1]/(x-1)x趋向于1=lim[x^(1/2)+1][x^(1/4)+1]/[x^(2/...