来自韩国才的问题
计算和方程:(1)先化简,再求值:x3−x2x2−x-1−x2x+1,其中x=2.(2)4x2−4+2x+2−1x−2(3)3x−1−2x+1=6x2−1(4)(-2ab)÷ab2a−b•12(b−a)2;(5)(a-aa+1)÷a2−2aa2−4•a+1a2+3a+2.
计算和方程:
(1)先化简,再求值:x3−x2x2−x-1−x2x+1,其中x=2.
(2)4x2−4+2x+2−1x−2
(3)3x−1−2x+1=6x2−1
(4)(-2ab)÷ab2a−b•12(b−a)2;
(5)(a-1−x2x+10)÷1−x2x+11•1−x2x+12.
1回答
2020-06-20 23:56