来自刘鑫荣的问题
已知sin(x+5π)=3/5,则sinx化简：cos(x-π/2)/sin(x+5π/2)·sin(x-2π)·cos(2π-x)=已知sinα=2根号5/5,α∈(π/2,π)则tanα=
已知sin(x+5π)=3/5,则sinx
化简：cos(x-π/2)/sin(x+5π/2)·sin(x-2π)·cos(2π-x)=
已知sinα=2根号5/5,α∈(π/2,π)则tanα=
1回答
2020-06-24 21:31