来自郭迎的问题
已知tanx=2,求2sin2x-sinxcosx+cos2x的值.
已知tanx=2,求2sin2x-sinxcosx+cos2x的值.
1回答
2020-06-24 21:59
已知tanx=2,求2sin2x-sinxcosx+cos2x的值.
已知tanx=2,求2sin2x-sinxcosx+cos2x的值.
∵tanx=2,
∴2sin2x-sinxcosx+cos2x
=2sin2x−sinxcosx+cos2xsin2x+cos2x
=2tan2x−tanx+1tan2x+1
=8−2+14+1
=75.