来自曹锦章的问题
(41+1/3)*3/4+(51+1/4)*4/5+(61+1/5)*5/6=?
(41+1/3)*3/4+(51+1/4)*4/5+(61+1/5)*5/6=?
1回答
2020-09-18 18:07
(41+1/3)*3/4+(51+1/4)*4/5+(61+1/5)*5/6=?
(41+1/3)*3/4+(51+1/4)*4/5+(61+1/5)*5/6=?
原式=124/3*3/4+205/4*4/5+306/5*5/6
=31+41+51
=123
这道题应先把括号算了然后再乘就很容易约分