来自蔡付东的问题
y=arctanx+1x-1的导数?
y=arctanx+1x-1的导数?
1回答
2020-01-29 09:06
y=arctanx+1x-1的导数?
y=arctanx+1x-1的导数?
y=arctanx+1x-1
y'=1/[1+(x+1x-1)^2]*(x+1x-1)'
=1/[1+(x+1x-1)^2]*(x+1)^22
=1/(1+x^2)